In pea plants, green pods (G) are dominant to yellow pods (g) and tall plants (T) are dominant to short plants (t). A scientist crosses a GgTt pea plant with a ggtt pea plant and the following offspring are produced: Phenotype Number of Offspring Green, tall 723 Yellow, short 749 Green, short 48 Yellow, tall 46 What is the percent recombination frequency for this cross

Explanation:

Given

Green pods (G) are dominant over yellow pods(g);

Tall plants (T) are dominant on short plant (t)

Parents are  GgTt ( Green tall)  and ggtt (yellow short), so their cross is;

Progeny;

Green tall 723.

Yellow short  749,

Green short 48,

Yellow tall 46

Green tall and yellow short are parental type, so they are non-recombinants;

so, 723 + 749= 1566 are non-recombinants;

Green short and yellow tall are recombinants ,

so  48+ 46=94  are recombinants;

Recombination frequency (RF)= Total no. of recombinants  progeny / total progeny ×100

Total progeny= 1566;

Total recombinants= 94

RF=  94÷1566×100

= 6.0025%

idk what the options are but

these is a strong electrostatic attraction between the ions hence a lot of energy is needed to overcome this attraction

this is why the boiling points are so high