G Dimples and long eyelashes are both autosomal dominant traits. If a woman with no dimples, who is heterozygous for long eyelashes, mates with a man who is heterozygous for dimples, and has short eyelashes, What are the chances that this couple produces a child who is heterozygous in EITHER trait?

1/4

Explanation:

The woman has no dimples which means that she is homozygous recessive for this locus (gg). She is heterozygous for long eyelashes which makes her genotype Ll for this locus.

The man is heterozygous for dimples (Gg) and has short eyelashes (ll).  

The probability of the progeny heterozygous for either trait can be calculated separately for each locus:

gg x Gg= 1/2 Gg: 1/2 gg

Ll x ll= 1/2 Ll: 1/2  ll

The total probability of progeny who is heterozygous for both locus= 1/2 Gg x 1/2 Ll= 1/4 GgLl

the answer would be knowledge about cars!