In the following tetrahybrid cross aabbccdd x aabbccdd what proportion of the f2 offspring would be expected to be genotypically aabbccdd?

a. 3/4
b. 1/2
c. 1/256
d. 81/256
e. 9/256

C. 1/256

Explanation:

In the tetrahybrid cross, we have different four groups. Let name them Part (A, B, C &  D).

Let Part A be Aa and Aa... If both traits crosses; we have

         A          a

A       AA        Aa

a        Aa        aa

Hence, there is a total of 4 combinations

Let Part B be Bb and Bb... If both traits crosses; we have

         B          b

B       BB        Bb

b       Bb         bb

Hence, there is a total of 4 combinations

Let C be Cc and Cc ... If both traits crossses; we have

         C           c

C       CC        Cc

c        Cc        cc

Hence, there is a total of 4 combinations

Let D be Dd and Dd... If both traits crosses; we have

         D          d

D       DD       Dd

d        Dd       dd

Hence, there is a total of 4 combinations

A genotype has the 4 groups together. Therefore the possible number of ways of forming the genotype = 4 x 4 x 4 x 4= 256

Now, Probability that the F2 offspring would be expected to be genotypically AABBCCdd =

=

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answer : haversian

[explanation: -(compact bone is organized as parallel columns, known as haversian systems, which run lengthwise down the axis of long bones. these columns are composed of lamellae, concentric rings of bone, surrounding a central channel, or haversian canal, that contains the nerves, blood vessels, and lymphatic system of the bone)]