How many molecules are formed from the cleavage of glucose during the first step of glycolysis?

The correct answer is- 2 molecules with 3 carbons

Explanation:

Glycolysis is the first step in both aerobic and anaerobic respiration. In glycolysis, glucose is broken down in the absence of oxygen into two molecules of pyruvate which consists of three carbons.

So in glycolysis, glucose is partially oxidized into two molecules of pyruvate. Then in aerobic respiration, this glucose is fully oxidized into CO2 in kreb's cycle. Glucose is a six-carbon compound so it gives 2 molecule of 3 carbon compounds during the first step of glycolysis.

So during this partial oxidation of glucose 2 ATP and 2 NADH is produced with 2 molecule of pyruvate which is a 3 carbon compound.

1) gene flow

- it is described as the transfer of genes from one population to another population so that frequency of gene is increased.

-a zebra migrates to join a different herd of zebras.

2) natural selection

- a mechanism of evolutionary change in which individuals with advantageous traits survive and reproduce whereas the others ( those that can not adapt) eliminate from the population.

-competition for sunlight leads to taller trees.

3) mutation

- permanent change in the nucleotide sequence of dna ( genetic material) that could have harmful or useful consequences.

-the dna of a snake changes to make its venom stronger.

4) genetic drift - it is a random phenomenon ( that occurs by chance such as fire) that results in change in the gene frequency in a small population.    

-a grassfire randomly sweeps through a population of buffalo and kills most of the animals.

explanation: