In pea plants, the gene for round seed (r) is dominant, and wrinkled seeds (r) are recessive. the endosperm of the pea is also either starchy, a dominant gene (s), or waxy (s). what cannot be said of a cross between two parents that are heterozygous for both traits?

None is wrinkled and waxy

Explanation:

Spliting the alleles and pairing them usng the two characters listed, The male pea plant will have four possible alleles: RS, Rs, rS, and rs. The female also we have the same. Using punnet's square, we are to cross the two parents, Using gentotypes obtained from this cross; RRSS, RRSs, RrSS, RrSs, RRSs, RRss, RrSs, Rrss, RrSS, RrSc, rrSS, rrSs, RrSs, Rrss, rrSs, rrss. The phenotupic ration will be 9 Round starchy: 3 Round waxy: 3 Wrinkled starchy: 1 wrinkled waxy. It cannot be said that none of the progeny will be wrinkled waxy.

c) 50% there are four chromosomes. after crossing over, 2 of the four have been changed. that means any gamete has a 2 in 4 chance or 50% chance of receiving the mutated chromosome.

a. seed plant structure. 1. the three main plant organs are roots, stems, and leaves. a fourth kind of tissue, meristematic tissue, is responsible for plant growth. meristematic tissue is the only plant tissue that produces new cells by mitosis. plants can lose water out of their leaves as they exchange gases with the air

explanation: