The genes for miniature wings (m) and garnet eyes (g) are approximately 8 map units apart on chromosome 1 in drosophila. phenotypically wild-type females (m + g / mg +) were mated to miniature-winged males with garnet eyes.

part a

which of the following phenotypic classes reflect offspring that were generated as a result of a crossover event?

select all that apply.

garnet eyes
wild type
miniature wings
miniature wings, garnet eyes
part b

if 800 offspring were produced from the cross, in what numbers would you expect the following phenotypes?

__wild type : __ miniature wings : __ garnet eyes : __ miniature wings, garnet eyes

enter your answer as the number of flies of each phenotype separated by a colon (example: 100: 300: 100: 300).

The following phenotypic classes reflect offspring that were generated as a result of a crossover event

Explanation:

When the miniature wings and garnet eyes links up with the 8 map unit that are present between them. After that the presence of two recombinant classes must complement together and make 8% of total i.e. they contribute 4% each. together the parental classes make up to 92% by contributing 46% one.

This can be understood through a phenotypic ratio calculation, which can be expected from it.

wild type: 4% x 800 = 32

miniature wings: 46% x 800 = 368

garnet eyes: 46% x 800 = 368

miniature wings, garnet eyes: 4% x 800 = 368

answer: - few nutrients

high pressure

low temperatures

explanation: 1. few nutrients:   open-ocean zone is located way far from the land, which is the main source of the essential nutrients.2. high pressure: pressure increases by 1 atmosphere for every 10 meters increase in depth.3. ample sunlight: a large fraction of the sunlight is reflected back to the atmosphere from the sea surface. 4. varying salinity: below the thermocline, the water is isolated from the atmosphere so the salinity remains stable over the year.5. low temperatures:   the temperature of open-ocean zone ranges from a low of -2°c to an average of 17°c