Phenylketonuria (pku) is a disease caused by a recessive mutation. pku is extremely common in ireland, affecting approximately 1 in 4500 live births. assuming that the population is in hardy-weinberg equilibrium, what is the frequency of homozygous wild-type individuals (i. e., people without the recessive mutation)? phenylketonuria (pku) is a disease caused by a recessive mutation. pku is extremely common in ireland, affecting approximately 1 in 4500 live births. assuming that the population is in hardy-weinberg equilibrium, what is the frequency of homozygous wild-type individuals (i. e., people without the recessive mutation)? 98.5% 2.96% 97% 1.5% 0.022%

97%

Explanation:

PKU is caused by a recessive mutation, which means that affected individuals are homozygous and recessive (tt).

The frequency of genotypes according to Hardy-Weinberg equilibrium is:

where p is the frequency of the T allele and q is the frequency of the t allele.

Affected individuals are 1 in 4500, which means the frequency of tt genotype is 1/4500.

If the population is in Hardy-Weinberg equilibrium,

The sum of the allele frequencies adds up to 1, therefore:

p + q = 1

p= 1 - q

p= 1 - 0.015

p= 0.985

The frequency of the TT genotype (homozygous wild-type individuals) will be:

97% of the population will have the homozygous wild-type TT genotype.

the answer is: reproductively

i think i spelled it wrong lol

anyways hope i

-lavira: )

answer: accepted answer: aquatic animals use the oxygen dissolved in water to carry out respiration. since the amount of dissolved oxygen in water is low as compared to the amount of oxygen in the air, therefore the rate of breathing in aquatic animals is much faster than it is in terrestrial animals.

explanation: