For a gene suspected of causing hypertension in humans, you observe the following genotype frequencies: a1a1 0.574; a1a2 0.339; a2a2 0.087. is this gene in hardy-weinberg equilibrium? why or why not? (assume that a difference of three percent or more in any of the observed versus expected frequencies is statistically significant.) see section 23.1 (page 458) .

This gene is in Hardy-Weinberg equilibrium

Explanation:

As per the second equation of Hardy-Weinberg equilibrium, sum of genotypic frequencies of all types with in a population must be equal to one

Frequency for genotype A1A1 ()

Frequency for genotype A2A2 ()

Frequency for genotype A2A1 ()

Now,

Substituting the given values in above equation, we get -

Hence, this gene is in Hardy-Weinberg equilibrium

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