Answer stat
a pea plant purebred to produce round yellow peas is crossed with a plant purebred to produce wrinkled green peas. round pea shape is dominant to wrinkled, and yellow pea color is dominant to green. members of the resulting f1 generation are then crossed to produce an f2 generation, as shown in the figure. on average, what fraction of the f2 generation will display both dominant traits?
a. 16 out of 16 plants will display both dominant traits.
b. 12 out of 16 plants will display both dominant traits.
c. 9 out of 16 plants will display both dominant traits.
d. 4 out of 16 plants will display both dominant traits.

option B,12 out of 16 plants will display both dominant traits.

Explanation:

Round (R)pea shape is dominant to wrinkled (r), and yellow (Y) pea color is dominant to green(y)

F1 generation - Round yellow peas is crossed with a plant purebred to produce wrinkled green peas.

So the genotype of offspring of F1 generations will be

RY * ry

RrYy

F2 generations - A cross is carried out between the offspring of F1 generation. Thus, The cross between "RrYy" and  "RrYy" is represented by the punnet square as below -

RY          Ry          rY          ry

RYRRYYRRYyRrYYRrYy

RyRRYyRRyyRrYyRryy

rYRrYYRrYyrrYY          rrYy

ryRrYyRryy          rrYyrryy

Hence, out of total 16, genotype rrYY  , rrYy, rrYy and rryy , do not have both dominant traits.

Rest all 12 have both the dominant traits.

Hence, option B is correct

i think that c)gold was found there

but i am not sure