Acollected gas has a pressure of 778mmhg and a temperature of 47.0c. what would be the new pressure at standard temperature

= 664.10 mmHg

Explanation:

According to pressure law the pressure of a fixed mass of a gas is directly proportional to the absolute temperature.

Therefore;

P1/T1 = P2/V2

Standard temperature is equal to 0°C, which is 273.15 K.

In this case;

P1/T1= P2/T2

P1 = 778 mmHg

T1 = 47.0 + 273 K

    = 320 K

P2 = ?

T2 = 0° C = 273.15 K

P2 =P1T2/T1

    = (778 × 273.15)/320 K

    = 664.10 mmHg

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