7. suppose that a dominant allele (p) codes for a polka-dot tail and a recessive allele (p) codes for a solid colored tail. if two heterozygous individuals with polka-dot tails mate, what's the probability of the phenotype and genotype combinations of the offspring?

a. 75 percent chance of a polka-dot tail and 25 percent chance of a solid colored tail (25 percent pp; 50 percent pp; 25 percent pp) b. 50 percent chance of a polka-dot tail and 50 percent chance of a solid colored tail (50 percent pp; 50 percent pp) c. 75 percent chance of a polka-dot tail and 25 percent chance of a solid colored tail (75 percent pp; 25 percent pp) d. 25 percent chance of a polka-dot tail and 75 percent chance of a solid colored tail (25 percent pp; 50 percent pp; 25 percent pp)

Hi!

The correct answer would be A.

As the allele P for polka dot is dominant to the allele p for solid color, it would yield a Polka dot tail in the individual in the presence of just one allele of P, while masking the effect of p for solid color.

So the possible genotypes and phenotypes would be as follows:

Following a cross by two heterozygous individuals, there would be 25 percent chance (1/4) of having the genotype pp , 25 percent (1/4) chance of having the genotype PP and 50 percent (2/4) chance of having the genotype Pp.

But the phenotype yielded by Pp and PP offspring would be polka dots, so there is a 75 percent (3/4) chance of having polka dot offspring, and 25 percent chance of having solid colored tail offspring.

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