Consider the following data. rates for cheetah population from 2011 to 2012 cause of change 2011 2012 deaths 2 1 births 5 4 immigration 6 1 emigration 8 3 which would have to happen to make the population growth of cheetahs in 2013 equal to the population growth observed in 2011 and 2012? a) 4 deaths, 7 births, 2 immigration, 6 emigration b) 3 deaths, 6 births, 5 immigration, 7 emigration c) 5 deaths, 2 births, 8 immigration, 3 emigration d) 1 deaths, 5 births, 3 immigration, 7 emigration

The correct answer would be B) 3 deaths, 6 births, 5 immigration, 7 emigration.

Population density of an area in a specified time can be calculated with the help of formula N = (B + I) – (D + E), where,

Thus, the population density in 2011 would be = (5 + 6) - (2 + 8) = 1.

Similarly, in 2012 the population density would be = (4 + 1) - (1 + 3) = 1.

Population density according to data provided in option B = (6 + 5) - (3 + 7) = 1.

Thus, correct answer would be option B

b on edge

Explanation:

answer: grassland biomes are closer to the equator and receive more rain.

grasslands are biomes that are dominated by grasses rather shrubs and trees. savanna are biomes that exhibit grasses, shrubs and small tree as vegetation. grasslands are located near the equator of the earth. these are found in north america. savanna biomes are found in africa, south america, australia and india. grassland exhibit moderate climatic conditions, it receives   amount of rainfall higher than savanna.   therefore, savanna exhibit dry and hot climatic conditions.