Brainliest asap! someone me : ) in one type of dog, black spots (b) are dominant over brown spots (b) and long tails (l) are dominant over short tails (l). complete a dihybrid cross for parents with the genotypes: bbll × bbll and answer the following in complete sentences. 1. describe how you would set up a punnett square for this cross. 2. list the likelihood of each possible offspring genotype. 3. list the likelihood of each possible offspring phenotype.

a)

Punnet square

BL         bL         BL           bL

BLBBLLBbLLBBLLBbLL

BlBBLlBbLlBBLlBbLl

BLBBLLBbLLBBLLBbLL

BlBBLlBbLlBBLlBbLl

b) Possible genotypes are

BBLL- 5

BbLL-5

BBLl-5

BbLl-5

c) Possible phenotype

Black spot and long tail - %

Explanation:

Given

a) black spots (B) are dominant over brown spots (b)

b) Long tails (L) are dominant over short tails (l)

A cross is carried out between BbLL × BBLl

Allele for BbLL are BL, bL, BL, bL

Allele for BBLl are BL, Bl, BL, Bl

1. Punnet square

BL         bL         BL           bL

BLBBLLBbLLBBLLBbLL

BlBBLlBbLlBBLlBbLl

BLBBLLBbLLBBLLBbLL

BlBBLlBbLlBBLlBbLl

2. Possible genotypes are

BBLL- 4

BbLL-4

BBLl-4

BbLl-4

Thus, out of total 16 possible offspring each genotype occurs four times. Thus the likelihood of each genotype is

%

2. Possible phenotype

BBLL- Black spot Long tail

BbLL-Black spot Long tail

BBLl-Black spot Long tail

BbLl-Black spot Long tail

All the 16 offspring have Black spot and long tail.

Thus the likelihood of offspring with Black spot and long tail is %

answer: all : )

explanation:

b is the correct answer