If a man is homozygous dominant for bent fifth finger and a woman is homozygous recessive. what is the probability that any offspring will have a bent fifth finger?

The probability of the offspring having a bent finger is 100% we can calculate this using a punnet square like one attached, where B is the dominant bent fifth finger and b is the recessive bent fifth finger, the man's genes are along the top and the woman's genes are along the side.

it would lead to upper respiratory infections and pneumonia.