Four forces are being applied to move an object to the left. force 1 is pushing to the right at 200 n. force 2 is pushing to the left at 500 n. force 3 is pushing to the right at 100 n. force 4 is pushing to the left at 50 n. what's the net force acting on this object? a. 0 n b. 650 n c. 250 n d. 850 n

The answer would be C. 250N.

Net force is defined as the sum of all forces acting on an object. But you need to take into account, the direction of the forces. All forces going to the right is usually positive, and those on going to the left is negative. Let's take your problem into account:

F1 = 200 N to the right (positive)

F2 = 500N to the left (negative)

F3 = 100 N to the right (positive)

F4 = 50 N to the left (negative)

Fnet = F1 + F2 + F3 + F4

Put in what you know with the proper sign:

Fnet = F1 + F2 + F3 + F4

Fnet = 200N +(-500N) + 100N + (-50N)

Fnet = 200N +(-500N) + 100N + (-50N)

Fnet = (-300N) + 100N + (-50N)

Fnet = (-200N) + (-50N)

Fnet = -250 N

Because the sign of the result is negative, we know that the force is to the left. So your final answer would be:

250N to the left

hey, i believe your answer would be d. sugar ribose and the base uracil. i believe this is the answer, because rna consists of sugar ribose, adenine, guanine, cytosine, and uracil.

your first option is incorrect, because that's dna. where it consists of sugar deoxyribose, adenine, guanine, cytosine and thymine.

your second option is also incorrect, this is because sugar deoxyribose is in dna, and uracil is in rna. these two do not make sense together.

your third option being incorrect, because sugar ribose is in rna, but not the base of thymine. rna consists of uracil, not thymine.

lastly your fourth option being correct! this answer is correct, because both sugar ribose, and the base uracil are in rna! ~

answer is d. sugar ribose and the base uracil.

not sure if this is what you'r looking for eubacteria and archaebacteria