There are 100 cats in a population that follows hardy-weinberg conditions. 4 cats display a recessive white coat color. how many of the cats are heterozygous?

We know that Hardy-Weinberg conditions include the following equations:

where

And where p = dominant, and q = recessive; this means that is equal to the homozygous dominant, is the heterozygous, and is the homozygous recessive .

So we have 100 total cats, with 4 having the recessive white coat color. That means we have a ratio of or 0.04. Let that equal our value.

So when we solve for q, we get:

Now that we have our q value, we can use the other equation to find p:

So then we can solve for our heterozygous population:

This is the ratio of the population. So we then multiply this number by 100 to get the number of cats that are heterozygous:

So now we know that there are 32 heterozygous cats in the population.

try using substitution:

x + y - 6 = x - y. (i'm not giving you the exact answer). since 0 = x - y, then sub 0 in the equation with x - y. combine your like terms, and then use inverse operations, and you'll have your answer.

: -)

i got you i did it ya know what it is just needing to fill this in for a quick task!