Why is ∆hf ° 62.4 kj/mol for i2 ( g., but 0.0 kj/mol for i2 (s)?

Opposite the ordinal equation, the reaction can become energy-absorbing,
 N2 (g) + four liquid (l) ---> a pair of NO2 (g) + four H2 (g),

delta H = 212.5 kJ/mol a pair of NH3 (g) > N2 (g) + three H2 (g)
 delta H = 100 and fifteen kJ/mol transfer those a pair of equations at constant time.

You get the equation needed and also the succeeding delta H is that the total of the several 
delta H: 4H2O (l) + 2NH3 (g) > 2NO2 (g) + 7H2 (g) , delta H = 327.5 kJ/mo