Ineed on 3,4,5,6,7,8 if you can show me the steps

The easiest way to find such limits, where there is a numerator and a denominator is to apply Hospital's Rule.
1st find the derivative of the numerator and the derivative of the denominator, if it still gives an indeterminate value, find the second derivative of N and D

3) lim sin(2x)/x when x →0
 Derivative sin2x → 2cos2x
 Derivative x→ 1
 2cos2x/1 when x→0 , 2cos2x → 2
 and lim sin(2x)/x when x →0 is 2

4) lim(sinx)/(2x²-x)

→cosx/(2x-1) when x →0 cosx/(2x-1) = -1
and lim(sinx)/(2x²-x) when x →0 is -1

and so on and so forth. Try to continue following the same principle

Horizontal asymptote at  tells us that the original graph has been translated down.since  ,  are positive.  also we can say that the point  has a smaller  -coordinate than  .this means that the  transformed exponential function is increasing as it goes to the right. as it goes from  to , the value of the exponential function increases. it goes from to something bigger, . therefore, as  . the left hand would be the side that approaches the horizontal asymptote.so the answer is d