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A particle moves along the X-axis so that its position at timet is given by x(t) = t^4 – t^3 – 4t^2 + 5t - 2. What is the velocity of the particle when its acceleration
is first equal to 0?

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A particle moves along the X-axis so that its position at timet is given by x(t) = t^4 – t^3 – 4t^2...
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