The side of a cube is decreasing at a rate of 9 millimeters per minute. At a certain instant, the side is 19 millimeters.
What is the rate of change of the volume of the cube at that instant (in cubic millimeters per minute)?

the  rate of change of the volume of the cube is  -9747 cubic millimeters per minute

Explanation:

The computation of the rate of change of the volume of the cube is given below:

As we know that

The volume of the cube is x^3

Now differentiate it with time t

So

dV÷ dt = 3x^2 dx ÷ dt

Now put the values

= 3(19)^2  (-9)

= -9747 cubic millimeters per minute

hence, the  rate of change of the volume of the cube is  -9747 cubic millimeters per minute

i do not get the question.