What is the limiting reagent when 1.5 moles of nitrogen react with 6 moles of hydrogen? N2(g)+3H2(g)—> 2NH3(g)

Explanation

Given

N2(g)+3H2(g)—> 2NH3(g)

Number of moles of nitrogen = 1.5 moles

Number of moles of hydrogen = 6 moles

Required: Limiting reagent

Solution

For Nitrogen:

For Hydrogen:

The limiting reagent is Nitrogen, because less moles of NH3 will be produced by nitrogen, meaning it all of it gets used up.

Answer

The limiting reagent is Nitrogen.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2